Old 03-06-2015, 01:31 AM   #1021
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Yaaaaaaaaaaaaaaa lets go on an adventure, king!
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Old 03-06-2015, 11:01 AM   #1022
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so strange not being the last poster on this thread for a month at a time
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Old 03-06-2015, 04:01 PM   #1023
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Boop
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Old 03-08-2015, 12:48 PM   #1024
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beep :{
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Old 03-09-2015, 11:36 AM   #1025
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Yaaaaaa
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Old 03-09-2015, 03:38 PM   #1026
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a
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Old 03-10-2015, 01:52 AM   #1027
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b
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Quote:
Originally Posted by Glitchless
If they put a nice icon on you it's beneficial if they put a mean one on the other guy it's detrimental.
Quote:
Originally Posted by Glitchless
The player was banned for using an exploit repeatedly without reporting it. There's only 1 proper way to profit off an exploit: report it.
Quote:
Originally Posted by Huggles
Old Delay/(1+haste%) = New Delay

For slow effects, use the slow % but as a negative.

Just repeat for multiple effects.

DO NOT multiply by 1+slow% to get your new delay. 1*1.4 is not the same as 1/0.6 and your answer will be wrong.
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Old 03-10-2015, 02:09 AM   #1028
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C
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Old 03-10-2015, 06:09 AM   #1029
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d
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Old 03-10-2015, 08:48 PM   #1030
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E
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Old 03-11-2015, 07:08 AM   #1031
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f
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Old 03-12-2015, 02:39 PM   #1032
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x
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Quote:
Originally Posted by Glitchless
They may have just gotten the squirts.
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Old 03-12-2015, 04:51 PM   #1033
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die
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Old 03-12-2015, 04:58 PM   #1034
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no u
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Quote:
Originally Posted by Glitchless
If they put a nice icon on you it's beneficial if they put a mean one on the other guy it's detrimental.
Quote:
Originally Posted by Glitchless
The player was banned for using an exploit repeatedly without reporting it. There's only 1 proper way to profit off an exploit: report it.
Quote:
Originally Posted by Huggles
Old Delay/(1+haste%) = New Delay

For slow effects, use the slow % but as a negative.

Just repeat for multiple effects.

DO NOT multiply by 1+slow% to get your new delay. 1*1.4 is not the same as 1/0.6 and your answer will be wrong.
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Old 03-12-2015, 07:51 PM   #1035
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...a? Foo!
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...a? Foo!



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Old 03-13-2015, 07:08 AM   #1036
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a
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Old 03-17-2015, 01:11 AM   #1037
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I peed on ryan butler
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Old 03-17-2015, 01:12 AM   #1038
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........F
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...a? Foo!



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Old 03-17-2015, 01:44 AM   #1039
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U
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Old 03-17-2015, 02:10 AM   #1040
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*posts and locks thread*
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Computing the probability that at least one of the following events will occur:
P(a or b ... or z) = 1 - P(!a and !b ... and !z)
Probability
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